In the given figure ,BD bisects angle ABC and angle ADC.Is triangle BAD congruent to triangle BCD?if so give reasons.Angle A and angle C is 90 degrees.
In ΔBAD and ΔBCD,
BD = BD (common)
∠BAD = ∠BCD = 90° (Given)
Now, BD bisects ∠ABC (Given),
⇒ ∠ABD = ∠CBD
Thus, by AAS congruency criteria,
ΔBAD is congruent to ΔBCD.