In the given figure determine the value of y and hence find (EOB,(FOA and (COD

From the figure EOF=COD  Vertically opposite anglesEOF=COD=5y  ....*Now BOC+COD+DOA=180°   Linear pair5y+5y+2y=180°12y=180°y=15°  ...1Now FOE+EOB+BOC=180°  Linear pair5y+EOB+5y=180°  EOB+10y=180°EOB+1015° =180°    using 1EOB+150°=180°EOB=30°Now, EOF+FOA+AOD=180°    Linear pair5y+FOA+2y=180°FOA+7y=180°FOA+715°=180°    using 1FOA=180°-105°=75°So, FOA=75°and EOF=COD=5y   using *COD=5y    COD=5×15°=75°   using 1COD=75°

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