In the given figure, O is the centre and AE is the diameter of the semicircle
ABCDE. If AB = BC and AEC = 50, then find
(a) CBE (b) CDE (c) AOB. Prove that BO||CE.

istill don't get it please tell me the anser

REMEMBER:ANGLE IN A SEMICIRCLE IS 90

can't u guys jus prove it 
other than giving obvious advice

< = ANGLE

let<BOA= X  

<COB = <BOA = X

AS EQUAL SEGMENT SUBTEND EQUAL ANGLE AT CENTRE

<BEA = <CEB= X/2 = 25⁰ ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC

• SO <AOB =50⁰

<OCE = 50⁰ ISOSCELES TRIANGLE

BY ANGLE SUM PROPERTY <COE = 80⁰

• <CBE = 40⁰ ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC
• <CDE = 140⁰ AS BCDE IS A CYCLIC QUARDILATERAL
• <BOC = <OCE = 50⁰ AS WE HAVE PROVED AND BY ANLTERNATE INTERIOR PROPERTY BO|| CE

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 hi patra i know this ques is from u like of maths

 < = (ANGLE)

let<BOA= X  

<COB = <BOA = X

AS EQUAL SEGMENT SUBTEND EQUAL ANGLE AT CENTRE

<BEA = <CEB= X/2 = 25⁰ ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC

• SO <AOB =50⁰

<OCE = 50⁰  (ISOSCELES TRIANGLE)

BY ANGLE SUM PROPERTY <COE = 80⁰

• <CBE = 40⁰ ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC
• <CDE = 140⁰ AS BCDE IS A CYCLIC QUARDILATERAL
• <BOC = <OCE = 50⁰ AS WE HAVE PROVED AND BY ANLTERNATE INTERIOR PROPERTY BO|| CE

 i dont know this answer is from ulike or not but i tried to solve it myself

good well done my friend tujhse yahi umeed thi