in the given figure O is the centre of the circle to triangle ACB and adb are grow inside the circle if [web = 135? then find {car and (dbe Share with your friends Share 0 Roopam Pandey answered this Dear student,In △ACE,∠AEB=∠ACE+∠CAE (Exterior angles property of triangle)∠ACE=90° AB is diameter and angle in semicircle is right angle.∠AEB=135°135°=90°+∠CAE ∠CAE =135°-90° ∠CAE =45°In △DEB,∠AEB=∠EDB+∠DBE (Exterior angles property of triangle)∠EDB=90° AB is diameter and angle in semicircle is right angle.∠AEB=135°135°=90°+∠DBE ∠DBE =135°-90° ∠DBE =45°Regards 0 View Full Answer