In the given figure, prove that AP bisects BAC - Maths - Triangles

Question

In the given figure, prove that AP bisects ∠BAC

Atul Shaw · Accepted Answer

Dear student,
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<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_6123829702c1b%20png"
style="width: 187px; height: 173px;">
in △NPA and △MPAPN=PM (from fig
)AP=AP (Common)∠PNA=∠PMA=90°So, by RHS criterion, △NPA≅△MPATherefore,∠NAP=∠MAP (CPCT)So, AP bisects ∠BAC can be concluded
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