In the track shown in figure section AB is a quadrant of a circle of 1.0 m radius. A block is released at A and slides without friction until it reaches point B. How fast is it moving at B, the bottom of the quadrant?

Dear Student,

Conservation of energy yields the equation,12mvB2+mghB=mghASo that,vB=2ghA-hBhA-hB=1 m  ......(given)vB=2×9.8×1=4.43 m

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