In this solution isnt (-h)^(1/2) an imaginary number???
Also how is sin(1/h) as h->0 = h as h->0???
Also in this question if its (-h)^(1/3) is a real number
Isnt this question a liitle incomplete???
If an odd root is considered then odd root of (-h) is defined in real numbers but an even root of (-h) is not defined in R
The answer given by meritnation expert is not satisfactory since lim h->0 always approaches 0 from positive side thats why in the formula for LHD f(c-h) -f(c)/-h (negative h is taken to make the poistive h negative)
If the h is already negative in the formula for LHD as said by meritnation expert then the formula for LHD will be same as that of RHD on putting h as negative value

In this solution isnt (-h)^(1/2) an imaginary number??? Also how is sin(1/h) as h->0 = h as h->0??? Also in this question if its (-h)^(1/3) is a real number Isnt this question a liitle incomplete??? If an odd root is considered then odd root of (-h) is defined in real numbers but an even root of (-h) is not defined in R The answer given by meritnation expert is not satisfactory since lim h->0 always approaches 0 from positive side thats why in the formula for LHD f(c-h) -f(c)/-h (negative h is taken to make the poistive h negative) If the h is already negative in the formula for LHD as said by meritnation expert then the formula for LHD will be same as that of RHD on putting h as negative value iPad lim 2:01 AM Page 10.10 sin lim sin Exit 96% lim