in triangle ABC, angle A is acute , BD CE r perpendiculars onAC AB prove that AB*AE=AC*AD Share with your friends Share 0 Manbar Singh answered this In ∆AEC and ∆ADB, ∠A = ∠A common∠AEC = ∠ADB 90° each⇒∆AEC ~ ∆ADB AA⇒AEAD = ACAB = ECDB Correponding sides of similar ∆'s are proportional⇒AEAD = ACAB⇒AE × AB = AC × AD 18 View Full Answer