In Triangle ABC ,Angle B=90 and BD perpendicular AC, if AC=9 cm and AD=3 cm then BD is equal to

1. 2√2 cm

2.3√2 cm

3. 2√3 cm

4. 3√3cm

Question

In Triangle ABC ,Angle B=90 and BD perpendicular AC, if AC=9 cm
and AD=3 cm then BD is equal to
1 2√2 cm
2 3√2 cm
3 2√3 cm
4 3√3cm

S. Usha Rani · Accepted Answer

${A B}^{2} + {B C}^{2} = {A C}^{2} {A B}^{2} + {B C}^{2} = 81... (1) F r o m Δ A B D, {A B}^{2} = 9 + {B D}^{2} {B C}^{2} = 36 + {B D}^{2} S u b s t i t u t i n g b o t h i n (1), 81 = 9 + {B D}^{2} + 36 + {B D}^{2} 81 - 9 - 36 = 2 {B D}^{2} 2 {B D}^{2} = 36 {B D}^{2} = 18 B D = \sqrt{18} = 3 \sqrt{2} c m$

In Triangle ABC ,Angle B=90 and BD perpendicular AC, if AC=9 cm and AD=3 cm then BD is equal to 1. 2√2 cm 2.3√2 cm 3. 2√3 cm 4. 3√3cm

In Triangle ABC ,Angle B=90 and BD perpendicular AC, if AC=9 cm and AD=3 cm then BD is equal to

1. 2√2 cm

2.3√2 cm

3. 2√3 cm

4. 3√3cm