in triangle ABC , if a2tanB=b2  tanA, then prove that the triangle is either right triangle or isosceles.

Dear student

asinA=bsinB=csinC=ka=ksinA , b=ksinB , and c=ksinC Now, a2tanB=b2tanAa2sinBcosB=b2sinAcosAa2cosAsinB=b2sinAcosBk2sin2AcosAsinB=k2sin2BsinAcosB2sinAcosA=2sinBcosB2sinAcosA-2sinBcosB=0sin2A=sin2B2A=2BSo triangle formed is isosceles triangleA=B
Regards

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