In triangle PQR,PQ=PR and S is any point on QR.prove that PQ2 -PS2=QS.RS Share with your friends Share 1 Lovina Kansal answered this Dear student Draw PT⊥QRIn △PTQ and △PTR, we havePQ=PRPT=PT [common]∠Q=∠R [∵PQ=PR]∴△PTQ≅△PTR⇒QT=RTSince △PTS and △PQT are right triangles right-angled at T.Therefore, PS2=PT2+ST2 and PQ2=PT2+QT2PQ2-PS2=QT2-ST2⇒PQ2-PS2=QT-STQT+ST⇒PQ2-PS2=QT-STRT+ST [∵QT=RT]⇒PQ2-PS2=QS.SR Regards 5 View Full Answer Nandini answered this I will give this answer after 2 hours . Okay.... -4 Mevin Abraham answered this MEE TOO -1