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in what ratio does the x-axis divide the segment joining the points (-4,-6) and (-1,7), also find the coordinates of point of division

let the ratio be k:1

a(-4 , -6) 

p(x,0)

b(-1,7)

now,  x = -1k -4 / k+1

0 = 7k -6 / k+1

7k = 6

k = 6/7

therefore, the ratio is 6:7

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The point of trisection of the line segment AB joining the points A(3,-2)and B(-3,4)are
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Answer is 6:7. First take the ratio as k:1,then use the section formula. Then substiutte 0 for the second equation. You will arrive at  the answer.
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Now m1:m2=6:7
Coordinate of division is
x=(6)(-1)+(7)(-4)/6+7
= -6-28/13
=-34/13

y=(6)(7)+(7)(-6)/6+7
=42-42/13
=0

Therefore (x,y) = (-34/13,0)
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 W by x,0
 
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 I mean why x,0
 
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What should we take 1,k
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s
 
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6,7
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6:7
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explain  the story of julius caesar in hindi and english

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6:7
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LET THE POINT CUTTING THE LINE SEGMENT BE P CUTTING IT IN THE RATIO m:n
P(x,0)
TO FIND THE RATIO WE TAKE,
y CO-ORDINATE OF P= {7m+(-6n)}/(m+n)         [AS PER THE FORMULA AND THE GIVEN DATA]
=> 0                                =7m-6n
​hence, m:n=6:7
                                          
 
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6:7
 
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Thank u
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the ratio is 6:7
the point is (-34/13,0)
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6:7
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Parvathi ,you better try to read complete question!!!
 
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Cheers ratio-6:7 coordinate are -34/13,0

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Ratio = 6:7 Coordinates = -34÷13,0

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In what ratio does x axis divide line segment
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