In which transition of a hydrogen atom ,photons of lowest frequency are
emitted?
1)n=4 to n=3
2)n=4 to n=2
3)n=2 to n=1
4)n=3 to n=1

Question

In which transition of a hydrogen atom ,photons of lowest frequency
are
emitted?
1)n=4 to n=3
2)n=4 to n=2
3)n=2 to n=1
4)n=3 to n=1

Jaya Mukkavili · Accepted Answer

Dear Student,

The formula for frequency of Photon due to transition of electron
from one energy state of hydrogen atom to the other is given
by-
Frequency of Photon emitted=ν =Rc1n12-1n22Here R =Rydberg constant and c=velocity of light
n1=Initial state and n2 = final stateWhen n1=3 and n2 =4Frequency =ν =Rc132-142 =0
049RcWhen n1=2 and n2 =4Frequency =ν =Rc122-142 =0
1875RcWhen n1=1 and n2 =2Frequency =ν =Rc112-122 =0
75RcWhen n1=1 and n2 =3Frequency =ν =Rc112-132 =9Rc
Thus the frequency of photon is minimum when there is a transition
from n = 4 to n=3
Regards

In which transition of a hydrogen atom ,photons of lowest frequency are emitted? 1)n=4 to n=3 2)n=4 to n=2 3)n=2 to n=1 4)n=3 to n=1

In which transition of a hydrogen atom ,photons of lowest frequency are
emitted?
1)n=4 to n=3
2)n=4 to n=2
3)n=2 to n=1
4)n=3 to n=1