integral of 1/(sinX +secX) dx

convery in sin and cos form-

cosx/(1+sinx cosx)

then rationalise. it will be ((cosx/(1-sin^2x cos^2x) - (cos^2x sinx/(1-cos^2x sin^2x))

then put sinx=t in one part and cosx = t in other. solve as usual..

some mistake in ur suggestion,

when you multiply & divide sec^{2 }x u will get it as sec^{2} x/(tan xsec x+sec^{3 }x) dx.

but, exact answer is too long and still many of them didn't solve.!!!!!!

multiply numerator and denominator by sec^{2}x

sec^{2}x/(tanx+sec^{2}x) =sec^{2}x/(tanx+1+tan^{2}x)

let tanx =t

=> sec^{2}x dx =dt

and solve the eq.in the form of 't'.

what is integral of log(x)??????

how to integrate

f (log(sin x ))dx

what is the 'ILATE' RULE