integral of te-Lt ? PROVIDE THE SOLUTION STEP WISE FOR BETTER UNDERSTANDING Share with your friends Share 0 Varun.Rawat answered this Let I = ∫t . e-lt dtTaking t as the first function and e-lt as the second function and using integration by parts, we gett × ∫e-lt dt - ∫ddtt ×∫e-lt dt dt + C=-t . e-ltl - ∫1 × -e-ltl dt + C=-t . e-ltl + 1l∫e-lt dt=-t . e-ltl -e-ltl2 + C 0 View Full Answer