integrate 1/[(x-a)(x-b)]1/2 Share with your friends Share 0 Manbar Singh answered this Let I = ∫dxx-ax-b=∫dxx2 - a+bx + ab=∫dxx2 - a+bx + a+b22 + ab - a+b22=∫dxx - a+b22 - a-b22=logx - a+b2 + x - a+b22 - a-b22 + C=logx - a+b2 + x2 - a+bx + ab + C 0 View Full Answer