Integration of sinx log(cosx)

​​-integral(log(t))dt
 
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take Cos x = t 
than differeciate it
now we get 
-sin x dx = dt 
integral[-log(t)dt
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Hope its ok

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Let log x be u and 1 be v then integrate from u into v formula

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Please friends give me answers

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Please solve the question below

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Hope u understand this..

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