Is burning of methane a double displacement reaction ??
Dear Student,
A Double Displacement Reaction is a bimolecular process in which parts of two compounds are exchanged to give two new compounds. The general equation used to represent double displacement reactions can be written as:
AB + CD → AD + BC
However, no such compositions are observed during the burning of methane. Hence, it is not a double displacement reaction.
Moreover, the burning of natural gas (CH4 or methane) is a combination reaction. When hydrocarbon fuels are burned, oxidation is occurring. Methane is getting oxidized. Oxygen is the oxidizing agent.
Now the question arises if it is a combination reaction, then why two products are formed? This is because in the case of oxygen it's very hungry, and well attaches itself to the atoms of hydrogen and carbon to make it oxides, through various stages until carbon dioxide and water are all that's left.
Regards
A Double Displacement Reaction is a bimolecular process in which parts of two compounds are exchanged to give two new compounds. The general equation used to represent double displacement reactions can be written as:
AB + CD → AD + BC
However, no such compositions are observed during the burning of methane. Hence, it is not a double displacement reaction.
Moreover, the burning of natural gas (CH4 or methane) is a combination reaction. When hydrocarbon fuels are burned, oxidation is occurring. Methane is getting oxidized. Oxygen is the oxidizing agent.
Now the question arises if it is a combination reaction, then why two products are formed? This is because in the case of oxygen it's very hungry, and well attaches itself to the atoms of hydrogen and carbon to make it oxides, through various stages until carbon dioxide and water are all that's left.
Regards