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it costs rs 2200 to bore a cylindrical hole at the rate of rs 100 per m3 if the diameter of the hole is 1m, what is its depth

Cost = rate * volume

2200 = 100V

volume = 22

volume of cylinder = pie * r2 * h

radius = diameter/2 = 0.5m

22 = 22/7 * 0.5 * 0.5 * h

h = 28

hence the depth of cylinder = 28m

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Cost = rate * volume

2200 = 100V

volume = 22

volume of cylinder = pie * r2* h

radius = diameter/2 = 0.5m

22 = 22/7 * 0.5 * 0.5 * h

h = 28

depth of cylinder = 28m

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Required to bore a cylindrical hole with

Diameter = 1m

So, its radius = 0.5 m

Also, we have given the cost of digging the hole which is Rs. 2200 at the rate of Rs. 100 per m3..

S, its volume = Rs. 2200 / Rs. 100 per m3

= 22 m3

Now, Its height

Volume of cylinder= TTr2h

= 22 / 7 x ( 0.5 )2 x h = 22 m3

= h = 28 m

Therefore, its depth is 28m..

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