Kindly answer this :

dear student,
let the three reaction be 1, 2  and 3 respectively
 now if we perform 1+2-3
then the resultant equation would be
K + 1/2O₂ + 1/2H₂ = KOH
Then the delta h of the above operation will be
=-68+(-48)-(-14)=-68-48+14=-102kcal
-102kcal is the answer
regards