( kindly donot give any link and donot ) explain each and every step of your answer donot use this formula tan(beta)= 
{vsin(theta)- gt }/vcos(theta):

8. A projectile is thrown in the upward direction making an angle of 60o with the horizontal direction with a velocity of 147 ms-1. Then, the time after which its inclination with the horizontal is 45o, is. 
(a) 15 s               (b) 10.98 s            (c) 5.49 s               (d) 2.745 s

Dear Student,vertical component ofthe velocity uy=147*sin60=14732ux=147cos60=1472the angle become 45 degree when vy=vxux remain constant .time taken t=14732-147210=147203-1=5.4 secRegards

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