Dear Student
Solution-
Object height (h) = 1cm
Object distance (u) = -15 cm [Object distance and focal length are taken negative in Concave mirror;New Cartesian Sign Convension]
Focal length (f) = -10 cm
We know, 1/v + 1/u = 1/f [Mirror formula]
Therefore, 1/v = 1/f - 1/u
1/v = 1/(-10) - 1/(-15)
1/v = 1/(-10) + 1/15 [(-) x (-) = (+)]
1/v = 5/(-150) [Cross-multiplying]
v = -150/5 = -30 cm
Image is -30 cm in front of mirror.
m = h'/h = -v/u [Formula of magnification]
Therefore,h' = -vh
h' = -(-30) x (1)/(-15)
h' = -2 cm
Image is real, inverted and enlarged
