Lesson factorisation exercise for 14 B part 21
Dear Student
2a + 2b - 3cx - 3bx + 2c - 3ax
Rearranging the terms and taking common, we solve further as follows:
= 2a + 2b + 2c -3ax - 3bx - 3cx
= 2(a + b + c) - 3x(a + b + c)
= (2 - 3x) (a + b + c)
Regards
2a + 2b - 3cx - 3bx + 2c - 3ax
Rearranging the terms and taking common, we solve further as follows:
= 2a + 2b + 2c -3ax - 3bx - 3cx
= 2(a + b + c) - 3x(a + b + c)
= (2 - 3x) (a + b + c)
Regards