Let a ,   b   and   c be non-zero vectors such that a × b × c = 1 3   b   c   a . If θ is the acute angle between the vectors b   and   c , then sin θ equals-
(A) 1 3                         (B) 2 3                    (C) 2 3                      (D) 2 2 3

Dear student
We have,a×b×c=13bca2a.cb-b.ca=13bcaa.cb=13bc+b.caa.c=0 and 13bc+b.c=0bc13+cosθ=013+cosθ=0cosθ=-13sinθ=223     using pythagoras theorem
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Answer is D)

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