Let f(x) = sgn(sgn(sgnx)) then limit x tends to 0 f(x) = ? Share with your friends Share 0 Vishvesh Kumar answered this f(x)=sgn(sgn(sgnx)) =sgn(sgnx)sgn(sgnx) by the definition of sgn function =1sgn(sgnx)×sgnxsgnx=1sgn(sgnx)×1sgnx×xxNow note that sgn(sgnx)=sgnx=1 as sgn funtion take value ±1So we have f(x)=11×11×xx=xxso we have left hand limit limx→0-f(x)=-1and right hand limit limx→0+f(x)=1 So L.H.L.≠R.H.L. Hence limit does not exit. 3 View Full Answer