lim(x-0) x*log(sin x)=A) -1 B) log e1 C) 1 D) None of thesethe answer is Bplease explain me how

limx0xlogsinx=limx0logsinx1x And w can see that when we will put x = 0 it is  form so, Using L'hospital rule, =limx0ddxlogsinxddx1x=limx01sin xddxsinx-1x2=limx0cos xsin x-1x2=limx0-x2cotx=0 as when x tends to o cotx tends to infinity but it is multiplied by zero so answer will be zero.
So answer will be D. But you have mentioned B as answer so kindly recheck your query.

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