Lim x tends to 0 1-cosx root cos 2x/x square Share with your friends Share 10 Manbar Singh answered this limx→0 1 - cos xcos 2xx2=limx→0 1 - cos xcos 2xx2 × 1 + cos xcos 2x1 + cos xcos 2x=limx→01 - cos2xcos 2xx21 + cos xcos 2x=limx→01 - cos2x1 - 2sin2xx21 + cos xcos 2x=limx→01 - cos2x + 2 sin2x . cos2xx21 + cos xcos 2x=limx→0sin2x + 2 sin2x . cos2xx21 + cos xcos 2x=limx→0sin2x1 + 2 cos2xx21 + cos xcos 2x=limx→0sin xx . limx→0sin xx . limx→01 + 2 cos2x1 + cos xcos 2x=1 × 1 × 1 + 21 + 1=32 36 View Full Answer
