Lim X tends to zero (1/x- log(1+x)/x^2) Share with your friends Share 11 Manbar Singh answered this limx→01x - log1+xx2=limx→0x - log1+xx2=limx→01 - 11+x2x Using L' Hospital's rule=limx→01+x-12x1+x=limx→0x2x1+x=limx→0121+x=121+0=12 2 View Full Answer
