limx->0 (1+sinx-cosx+log(1-x) )/x3.solve with the help of sandwich theorem . Share with your friends Share 3 Neha Sethi answered this Dear student Solving this question with the help of Sandwich theorem is not a part of your syllabus,as the theorem is taught in graduation.But at the same time we can solve this question by L'Hopitals rule.We have:limx→01+sinx-cosx+log1-xx3It is the of the form 00.So, By L'Hopitals rule, required limit islimx→0cosx+sinx-11-x3x2It is the of the form 00.So, By L'Hopitals rule, required limit islimx→0-sinx+cosx-11-x26xIt is the of the form 00.So, By L'Hopitals rule, required limit islimx→0-cosx-sinx-21-x36=-cos0-sin0-21-036=-1-26=-36=-12 Regards -3 View Full Answer
