log3{5 + 4log3(x-1) } = 2 , then x = ?

a) 2
b) 4
c) 8
d) log2*16

Answer it soon

log₃{5+4log₃(x-1)}=2

5+4log_​3(x-1)=9

4log₃(x-1)=4

log₃(x-1)=1

x-1=3 => x=4

Hence, (B) is correct