Dear Student, We have;log38log916We can write it as,log8log3log16log9 Using base change formula : logab=logblogalog23log3log24log323log2log34log22log33log2log32log34log232 Regards

log₃8 / log₉16

Dear Student,

W e h a v e; \frac{\log_{3} 8}{\log_{9} 16} W e c a n w r i t e i t a s, \frac{\frac{\log 8}{\log 3}}{\frac{\log 16}{\log 9}} [U \sin g b a s e c h a n g e f o r m u l a : \log_{a} b = \frac{\log b}{\log a}] \frac{\frac{\log 2^{3}}{\log 3}}{\frac{\log 2^{4}}{\log 3^{2}}} \frac{\frac{3 \log 2}{\log 3}}{\frac{4 \log 2}{2 \log 3}} \frac{3 \log 2}{\log 3} \frac{2 \log 3}{4 \log 2} \frac{3}{2}

Regards.

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log38 / log916

log₃8 / log₉16