meritnation experts i didn't get the example 2 - Maths - Data Handling

Question

meritnation experts i didn't get the example 2 ?

Ankush Jain · Accepted Answer

In the said example, we have thrown a dice and we have to find out the probability of occurrence of following cases:

the number 2
any one of the number among 1, 2, 3, 4, 5, and 6
the number 7

Solution:

Firstly, we will find the total number of possible outcomes when a dice is thrown. We know that when a dice is thrown, there are only six possible outcomes i.e., 1, 2, 3, 4, 5, and 6.

Now, all these outcomes will have the same possibility of occurrence as any of them can come when a dice is thrown.

i) probability of getting the number 2

Out of six possible outcomes, the number 2 will appear only once.

Therefore, number of favourable outcomes = 1

And total number of outcomes = 6

$S o, p r o b a b i l i t y o f g e t t i n g n u m b e r 2 = \frac{n u m b e r o f f a c v o u r a b l e o u t c o m e s}{t o t a l n u m b e r o f o u t c o m e s} = \frac{1}{6}$

ii)

probability of getting any one of the number among 1, 2, 3, 4, 5, and 6

Again, when a dice is thrown, we can get any one of the numbers among 1, 2, 3, 4, 5, and 6.

Therefore, number of favourable outcomes = 6

And total number of outcomes = 6

$S o, p r o b a b i l i t y o f g e t t i n g t h e n u m b e r 1, 2, 3, 4, 5, 6 = \frac{n u m b e r o f f a c v o u r a b l e o u t c o m e s}{t o t a l n u m b e r o f o u t c o m e s} = \frac{6}{6} = 1$

iii) probability of getting the number 7

When a dice is thrown, there is no possibility of getting the number 7, as the number 7 doesn't appear in any outcome.

Thus, the probability of getting the number 7, when a dice is thrown, is 0.

Hope you get it!!