monochromatic light of wavelength 400 mm and 560 mm are incidents simultaneously and normally on double slit apparatus whose slit separation is 0.1 mm and screen distance is 1 m.distance between areas of total darkness will be
Let nth minima of 400nm coincides with m th minima of 560nm, then
FORMULA : (2n-1)λ/2
(2n-1)(400/2) = (2m-1)560/2
2n-1/2m-1=7/5
10n-14m+2=0
By inspection m=3,n=4 and m =8, n=11
i.e, 4th minima of 400 nm coincides with 3rd minima of 560 nm.
Location of this minima is,
FORMULA : Y = {(2n-1)D*λ}/2d
Y1 = (2 x 4 -1)(1000)(400 X 10-6)2 X 0.4 = 14 mm.
Next 11 th minima of 400 nm will coincide with 8th minima of 560nm
Y2 = (2 X 11 - 1)(1000) (560 X 10 -6)2 X 0.1 = 42 mm
Required distance is Y2 - Y1 = 28 mm.