Nine times the side of one square exceeds the perimeter of a second square by one meter and six times the area of the second square exceeds twenty nine times the area of the first square by one square meter. Find the side of each square.

Let the side of first square be x m and that of second square be y m.

**Given, **nine times the side of one square exceeds the perimeter of a second square by one meter.

Again, it is given that six times the area of the second square exceeds twenty nine times the area of the first square by one square meter.

Now, y ≠ -5/11, as the side of a square can't be negative.

On putting value of y = 11 in (1), we get

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