∀ n ∈ N , 1 + 2 x + 3 x 2 + . . . . + n . x n - 1 = ( x ∈ R , x ≠ 1 ) 1 ) 1 - ( n + 1 ) x n + n . x n + 1 ( 1 - x ) 2 2 ) ( n + 1 ) x n ( 1 - x ) 2 3 ) 1 - ( n + 1 ) x n + n . x n + 1 ( 1 + x ) 2 4 ) ( n - 1 ) x n ( 1 + x ) 2 Share with your friends Share 0 Brijendra Pal answered this Hi, 0 View Full Answer