no 12 a)

Q12.(a) In the figure (1) given below, ABCD and AEFG are two parallelograms. Prove that area of  || gm ABCD = area of || gm AEFG.

              

 

construct line GB
1/2 llgm ABCD = triangle AGB(llgm and triangle are in same base than triangle is half of parallelogram)  ......eq(1)
1/2 llgm AEFG = triangle AGB (llgm and triangle are in same base than triangle is half of parallelogram) ......eq(2)
compare eq 1 and 2
therefore​          1/2 llgm ABCD = 1/2 llgm AEFG
                                llgm ABCD=llgmAEFG