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Adjoint and inverse of a matrix and solution of Linear simultaneous equations by matrix method.


6.
    ​Find the inverse of each of the following matrices by using elementary column operation :

i       - 6       4     2 - 2                         i i         5 - 4 - 3       3                   i i i         - 3 5 - 4 5                     i v             7 8 2 2                       ( v )           cos   θ   - sin   θ sin   θ       cos   θ

Dear student
A=-642-2We have, A=AI-642-2=A1001R1R1-61-232-2=A-16001R2R2-2R11-230-23=A-160131R2R2×-321-2301=A-160-12-32R1R1+23R21001=A-12-1-12-32Hence A-1=-12-1-12-32
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