Dear student We have,We have,a×b=absinθSo, a×b2=a2b2sin2θa×b2=a2b2-a2b2cos2θa×b2=a2b2-abcosθ2a×b2=a2b2-a,b2a×b2+a b2=a2b2 Regards

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Dear student

We have, We have, |a \times b| = |a| |b| sinθ So, {|a \times b|}^{2} = {|a|}^{2} {|b|}^{2} \sin^{2} θ {|a \times b|}^{2} = {|a|}^{2} {|b|}^{2} - {|a|}^{2} {|b|}^{2} \cos^{2} θ {|a \times b|}^{2} = {|a|}^{2} {|b|}^{2} - {(|a| |b| cosθ)}^{2} {|a \times b|}^{2} = {|a|}^{2} {|b|}^{2} - {(a, b)}^{2} {|a \times b|}^{2} + {(a . b)}^{2} = {|a|}^{2} {|b|}^{2}

Regards