Number 24......solve ...plzz plzz

Dear Student ,

T a k i n g L . H . S \frac{1 - \tan^{2} θ}{c o t^{2} θ - 1} = \frac{1 - \tan^{2} θ}{\frac{1}{\tan^{2} θ} - 1} [u \sin g c o t^{2} θ = \frac{1}{\tan^{2} θ}] = \frac{\frac{1 - \tan^{2} θ}{1}}{\frac{1 - \tan^{2} θ}{\tan^{2} θ}} = \tan^{2} θ R . H . S H e n c e P r o v e d

Regards