Number of ways in which 3 persons throw a normal die to have a total score of 11 is - Maths - Permutations and Combinations

Question

Number of ways in which 3 persons throw a normal die to have a
total score of 11 is ??

Anuradha Sharma · Accepted Answer

For making a total of 11 we get, 11=1+4+6 total 6 ways by 3!=2+3+6 total 6 ways by 3!=2+4+5 total 6 ways by 3!=3+4+4 total 3 ways by 3!2=1+5+5 total 3 ways by 3!2=5+3+3 total 3 ways by 3!2So total number of ways = 6+6+6+3+3+3=27 ways

Number of ways in which 3 persons throw a normal die to have a total score of 11 is..??