Obtain the differential equation of the family of circles passing through (a,0) and (-a,0). Share with your friends Share 13 Rahul Raj answered this Dear student (a,0) and (-a,0)midpoint is (0,0)The center of these circles necessarily lie on the y axis, the perpendicular bisector of chord passes through centre This implies that their center can be represented as (h,k) where h=0 By Pythagoras theorem, the radius of such circle can be given by r =a2+k2 Now just substitute these values in the standard equation: x2 + (y-k)2= a2+k2differentiating we get2x+2(y-k)dydx=0dydx=-xy-k Regards -59 View Full Answer