Of all the rectangles each of which has a perimeter 40 m find which one had maximum area.find the area also. Share with your friends Share 3 Ashwini Kumar answered this Let l and b be the length and breadth of rectangle and A is its area.perimeter=2l+b⇒40=2l+b⇒20=l+b⇒b=20-l .....1Now,A=lb⇒A=l20-l⇒A=20l-l2Differentiating both sides w.r.t. l, we getdAdl=20-2lFor the maximum area, its derivative will be zero.∴dAdl=0⇒20-2l=0⇒2l=20⇒l=10 mPutting l=10 m in 1, we getb=20-10=10 m∴When length and breadth both are equal to 10 m, area will be maximum.Area=lb=10×10=100 m2 7 View Full Answer Lokeswar Kaushik Sravan answered this Area will be maximum when both L,B=10. but the it is a square then.so,the one with L=11 and b=9 wil be rectangle with the maximum area=99. You can also say when L=10.1and B=9.9 is the rectangle with maximum area=99.99. -2