one litre of gas at stp weight 1.16g it can be possible be
a) C2H2
b) CO
c) O2
d) CH4
Dear Student,
According to Avogadro's law, 1 mole of every gas occupies 22.4 L at STP and weighs equal to its molar mass.
So, 1 mol of gas at STP = 22.4 litre
1 L of gas weight 1.16 g
1 mol weight = 22.4 * 1.16 = 26 g
The correct option will be the molecule with molar mass 26g.
(a) C2H2 has molar mass = 26g
(b) CO has molar mass = 28g
(c) O2 has molar mass = 32g
(d) CH4 has molar mass = 16g
So,out of the above fourr options , (a) is the correct option.
Regards
According to Avogadro's law, 1 mole of every gas occupies 22.4 L at STP and weighs equal to its molar mass.
So, 1 mol of gas at STP = 22.4 litre
1 L of gas weight 1.16 g
1 mol weight = 22.4 * 1.16 = 26 g
The correct option will be the molecule with molar mass 26g.
(a) C2H2 has molar mass = 26g
(b) CO has molar mass = 28g
(c) O2 has molar mass = 32g
(d) CH4 has molar mass = 16g
So,out of the above fourr options , (a) is the correct option.
Regards