OUT OF 60 STUDENTS 25 FAILED IN PAPER-I,  24 IN PAPER-II,   32 IN PAPER-III,  9 IN PAPER-I ALONE,  6 IN PAPER-II ALONE,5 IN PAPER-II AND PAPER-III,  3 IN PAPER-I AND PAPER-II, THEN HOW MANY FAILED IN ALL PAPERS, HOW MANY PASSED IN ALL PAPERS 

U = 60

n(A) = 25

n(B) = 24

n(C) = 32

n(A-(B U C)) = 9

n(B-(A U C)) = 6

n(A ∩ B) = 3

n(B ∩ C) = 5

n(A ∩ B ∩ C) = ?

U - (A U B U C) = ?

Now using this data u can solve

According to me u haven't mentioned data correctly. 

Still.

Answer came.,.

10  failed all exams , 10 passed.