p is a point in the interior of angle aob pm perpendicularoa and pn perpendicular ob if angle aob  35 measure of mpn

Answer :

Given  : $\angle$ AOB  = 35$°$ , and PM perpendicular on OA and PN perpendicular on OB  , So

$\angle$ PMO  = 90$°$
And
$\angle$ PNO  = 90$°$


We know from angle sum property of quadrilateral , Sum of all internal angles of quadrilateral is 360$°$  . So,

$\angle$ AOB  + $\angle$  PMO  +  $\angle$  PNO  +  $\angle$  MPN  = 360$°$ , Substitute all values , we get

35$°$  + 90$°$  + 90$°$  + $\angle$  MPN  = 360$°$

$\angle$  MPN  = 360$°$ - 215$°$

$\angle$  MPN  = 145$°$                                                                         ( Ans )