P, Q and R are the mid-points of sides BC, CA and AB respectively of ∆ABC.                   Prove that : AC + 2BQ > AB + BC 

Dear Student,



In ABQ,AQ+BQ>AB Sum of any two sides of triangle is greater than third sideIn CBQ,CQ+BQ>BC Sum of any two sides of triangle is greater than third sideThus, AQ+BQ+CQ+BQ>AB+BCi.e. AQ+CQ+2BQ>AB+BCi.e. AC+2 BQ>AB+BC

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Very easy question next question pls
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