P's income is 10% less than that of q. How much percent is q's income more than that if p's? Pls solve it don't share link

Hi, Lets Q's income = Rs. 100so income of P = 100-10% of 100 = 100-100×10100= 90 now Q's income is more than by P = 100-90 = 10 in terms of % = difference of income P's income×100= 1090×100= 1119%

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