Page no- 180 Figure - 11.3
(a) Solution of which chamber has a
lower water potential?
(b) Solution of which chamber has a
lower solute potential?
(c) In which direction will osmosis
occur?
(d) Which solution has a higher solute
potential?
(e) At equilibrium which chamber will
have lower water potential?
(f) If one chamber has a Ψ of – 2000 kPa,
and the other – 1000 kPa, which is
the chamber that has the higher Ψ?

May be it helps you

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(a)B (b)B (c)A-B (d)A (e)None (f)A
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how the answer of d is A that should be B

 

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TQ SOO
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a) B b) B c) A-B d) A e) none f)1000 kPa
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For d it should be B not A
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a)B b)B. Because solute potential is always negative and so B has lower solute potential c)A->B d)A. Because solute potential is always negative and so it has higher solute potential e)at equilibrium all are equal f)1000kPa
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How to calculate last question?
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a) B has lower water potential as it has more solute molecules and less free water mol. b) B has lower solute potential as more the number of solute the more negative (or less) is solute potential. c) A->B as osmosis movement occurs from the region of lower concentration to the higher d) A has higher solute potential as it has less solute particles ( means less negative solute potential) as comparable to B e) None. At equilibrium both will have same water potential. f) -1000kpa ( less negative value of pressure potential comparing to the former)
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b would be A and d would be B
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B. b. a to b. a. none. b.
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a) B have lower water potential, since there is more concentration of solute in B than A. b) A have lower solute potential, since the concentration of solute is less in A. c) the osmosis will occur from A to B, since the water potential (concentration) is high in A and low in B and osmosis occurs from higher water potential to lower water potential. d) B have higher solute potential since it has more concentration of solute than A. e) At equilibrium, the water potential will be equal in both the Chambers. f) The chamber with higher potential is the chamber that have a potential of 2000 kPa which will be A.
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There is a small correction!! I answered the f) question wrong!!! I corrected it and have poster the answer again!!! a) B have lower water potential, since there is more concentration of solute in B than A. b) A have lower solute potential, since the concentration of solute is less in A. c) the osmosis will occur from A to B, since the water potential (concentration) is high in A and low in B and osmosis occurs from higher water potential to lower water potential. d) B have higher solute potential since it has more concentration of solute than A. e) At equilibrium, the water potential will be equal in both the Chambers. f) The chamber with higher potential is the chamber that have a potential of -1000 kPa which will be A.
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Answer is following

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All of Ur answer are confusing, no one is clear ab their ans.
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Hope this will help you

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(a) B (b)B (c)A-B (d)A (e)none (f)-1000kPa
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a) B
b) A
c) A to B
d) B
e) at equilibrium A will have lower water potential then intial.
f) chamber having -1000kPa will have higher value.
 
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(a)B (b)B (c)A-B (d)A (e)None (f)A
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(b)A or B??????
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Thank you
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Lower refers to having more negative value

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Wrong
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For solute potential if magnitude is asked then B is max but for value including sign then A is more as it is closer to zero..
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Page no.180 11th class osmosis
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Plz explain that how tha ans of f is A?
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