Passage 2) Solve:
Given the equations of two sides of a square as 5 x + 12 y - 10 = 0 ,   5 x + 12 y + 29 = 0 . Also given is a point M(-3, 5) lying on one of its sides . Answer the following questions

28) The number of possible squares must be
(A) One
(B) Two
(C) Four
(D) None of these

29) The area of the square must be
(A) 9 units
(B) 6 units
(C) 5 units
(D) None of these

30) If the possible equations of the remaining sides is 12 x - 5 y + λ = 0 then? cannot be.
(A) 61
(B) 22
(C) 100
(D) 36

Dear student
Q 29The equations of given lines are5x+12y-10=0  ...15x+12y+29=0    ...2Clearly the length of the side of the square is equal to the distance between the lines1 and 2So from (1)   5x=10-12yPut y=0 5x=10x=2So, 2,0 is a point lie on the line 1So length of the perpendicular from point   2,0 to the 2 is given byd=52+120+2952+122        d=Ax1+By1+CA2+B2d=10+2913=3unitsSo the length of the square is 3 unitsArea of square=side2=32=9sq units
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