pl answer Q 16
pl answer Q 16 CHEMICAL TH RMODYNAMI Column •I A) Adiabatic expansion of a gas C) AG=AH+T D) —R for monoatomic ideal gas OBJECTIVE CHEMISTRY-XIB Column-II Q) Isoentropie S) TV 7-1 = constant 24. 25. 11 Section - D 16. The enthalpy change involved in the oxidation Of glucose*s —3000KJ/moI 25% Of this energy is available for muscular work If 100 KJ muscular work is needed to walk I kilometre, the maximum distance that a person Will be able to walk after eating 144 gm Of glucose is 17. The enthalpy of hydration Of Na• and Cl- ions are in the ratio a : b. The lattice energy of NaCl solid is 772 KJ/mol, enthalpy of its solution is 2KJ/mo/. The enthalpy of hydration of Ct- ion is 350 KJ/mo/. If b is 5/2, what is a ? 18. Look at the following diagram 80 40 PROGRESS OF REACTION The enthalpy change for the reaction A will be —x2kJ ,The value of x is 19. Heat of neutralisation of a polybasic acid by strong base is —54.8 kcal mol-l. What is basicity of the acid 20. Calculate the standard internal change in multiples of —102 KJ for the reaction OF2(g) + H20(g) 2HF at 298K. The standard enthalpies of formation of OF2( , H20(g), HF(g) are +20, +250 and — 270 KJ mole-I 21. For a liquid, enthalpy of fusion is 1.435 kcal mol-l and molar entropy change is 5.26 cal mol-1K-1. The freezing point of liquid in celcius will be 22. The value of logK for the reaction A is I Ox. (A HO --54.07KJmorl ; R = 8.314 JK-I mol-l ; A so = 10JK-1mo/-1 ) calculate the value of 'x' r298K 23. In how many of the following entropy increases ? a) +2NH3( ) c) -+H20(9 b) PC15cg) +C12(gj e) 2NaHC036) f) NH2C02NH4 2(g) g) H20(l) -*H206) 132 APEX SERIES for Sri Chaitany

1 mol of glucose on oxidation gives =-2880 kJ (-ve means  energy released)

  But only 25% of the energy is available for muscular work

  So , energy available for muscular work = (25/100) x total energy

   = (25/100)x2880=720KJ

  100KJ OF energy will work 1 km of walk

  1 KJ of energy will work= 1/100 km

  720 KJ of enegy will work=(1/100)x720

  = 7.2 km

  So 1 mol of  glucose will give 720 kj muscular energy to walk 7.2 km

  1 mol of glucose = 180 g (molar mass of glucose)

  180 g of glucose will work =7.2 km walk

  1g of glucose will work= 7.2/180 km of walk

  144 g of glucose will work= (7.2/180)x144

  =5.76 km walk

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