pl answer Q 16
1 mol of glucose on oxidation gives =-2880 kJ (-ve means energy released)
But only 25% of the energy is available for muscular work
So , energy available for muscular work = (25/100) x total energy
= (25/100)x2880=720KJ
100KJ OF energy will work 1 km of walk
1 KJ of energy will work= 1/100 km
720 KJ of enegy will work=(1/100)x720
= 7.2 km
So 1 mol of glucose will give 720 kj muscular energy to walk 7.2 km
1 mol of glucose = 180 g (molar mass of glucose)
180 g of glucose will work =7.2 km walk
1g of glucose will work= 7.2/180 km of walk
144 g of glucose will work= (7.2/180)x144
=5.76 km walk